|
|
Mensuration - Quant/Math - CAT 2013
Question 4 the day:
September 30, 2003
The question for the day is from the topic of Mensuration.
- The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel?
| (1) |
20 ft |
| |
(2) |
25 ft |
| (3) |
750 ft |
| |
(4) |
900 ft |
Correct Answer - (4)
Solution:
The circumference of the front wheel is 30 ft and that of the rear wheel is 36 feet.
Let the rear wheel make n revolutions. At this time, the front wheel should have made n+5 revolutions.
As both the wheels would have covered the same distance, n*36 = (n+5)*30
36n = 30n + 150
6n = 150
n = 25.
Distance covered = 25*36 = 900 ft.
|
|
|
|
